Django +ajax +mongodb integration.
Hey everyone,I am begginer in django and implementing a project which has a login page and registration page and once the users will enter details in registration page then it should be stored in MongoDB and on another page I want to display that data in table format so and for that, I am using ajax but it is failing. And another question is do i need to write script for connecting mongodb or " djongo " will work.Please help.
I am using : Django 2.0.7 python 3.7
here's the code register.html
......
<p class="test"></p>
<table id="table" class="hidden" border="1">
<tr>
<thead>
<tr>
<th>Name</th>
<th>Mobile Number</th>
<th>Gender</th>
<th>Delete</th>
<th>Edit</th>
</tr>
</thead>
<tbody id="table-body">
{% for i in result %}
<tr>
<td id="na">
{# {{ i.name }}#}
</td>
<td>
{# {{ i.Mobile_num }}#}
</td>
<td>
{# {{ i.Gender }}#}
</td>
<td>
{# <button id='{{ i|mongo_id }}' class='botaoadd' name='delete'>delete</button>#}
</td>
<td>
{# <button id='{{ i|mongo_id }}' class='btupdate' name='update'>update</button>#}
</td>
</tr>
{% endfor %}
</tbody>
</table>
</body>
<script type="text/javascript">
var obid1;
$("#submit").click(function (e) {
var fname = $("#fname").val();
var mno = $("#mno").val();
var gen = $('input[name=gender]:checked').val();
var datas = {
"Name": fname,
"Mobile_num": mno,
"Gender": gen,
};
store_table(datas)
get_my_table()
});
$("#table").on("click", ".btupdate", function (e) {
obid = $(this).attr('id')
$("#submit").hide()
$("#edit").show()
$("#cancel").show()
obid1 = obid
var d_update = {
"oid": obid,
"action": "get_entry"
}
$.ajax({
url: "/get_entry",
type: "POST",
data: d_update,
success: function (response) {
$("#fname").val(response[0]["name"])
$("#mno").val(response[0]["Mobile_num"])
},
error: function (response) {
console.log("This is after clicking edit button")
}
})
})
$("#cancel").click(function (e) {
$("#submit").show()
$("#edit").hide()
$("#cancel").hide()
$("#fname").val("")
$("#mno").val("")
})
def update_view(request, *args, **kwargs): #this method updates the entry in database using the object id
try:
if request.method == 'POST':
customer_dict1 = dict()
request_body = request.POST
customer_dict1["_id"] = request_body.get("_id")
customer_dict1["name"] = request_body.get("Name")
customer_dict1["Mobile_num"] = request_body.get("Mobile_num")
customer_dict1["Gender"] = request_body.get("Gender")
result = database.customer_info.update({"_id": ObjectId(customer_dict1["_id"])},
{"$set":{"name":customer_dict1["name"],"Mobile_num":customer_dict1["Mobile_num"],
"Gender":customer_dict1["Gender"]}})
return HttpResponse("successfully updated")
result = get_db()
print(result)
return render(request, 'dashboard/register.html', {"result": result})
return render(request, 'dashboard/register.html', {})
except Exception as e :
return HttpResponse("failed")
so in this it showing httpresponse as failed