🔒 Mini RSA PicoCTF

Files Given: N = <large 1024‑bit modulus> e = 3 ciphertext c = <another large integer> Goal: Recover the plaintext flag. 🕵️‍♂️ What’s the vulnerability? The exponent e = 3 is small. Normally, this term allows c^(1/3) to be computed easil...