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Vaibhav Dhiman
Infinite currying one liner
const mu = (num1) => (num2) => num2 ? mu(num1 + num2) : num1;
Pujarini Jena
Software Developer
Hey Vaibhav!
Thanks for trying out. The question was to write one line solution for
const sum = function(a) { return function(b) { if (b) { return sum(a + b); } else { return a; } } }