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It will run three times and will only stop the 4th time when the condition of execution of 3 times ( j<= 3 ) is met. That value was 4. It will remember the value of j from the last iteration of the loop and show 4.

And it won't even execute the inner block those three times just because "j" is a var? Ayesha Sahar

The main function is only executed thrice and we get the answer accordingly. What is happening is that since it's a closure, it will store the value after j<= 3, which is 4, when it is stopping. Hence, that value will be stored in j and only that will be accessible, that's why we see 4. In order to avoid this case, where we only get the value of the end, we use the solutions mentioned! Nirmal Shah

Got it, thank you! Ayesha Sahar